SOLUTION: Suppose we have a 400 liter mixture of acid solution, which is 10% acid, and 90% water. Let V be the number of liters of pure water to add to the mixture so that it is a 8% acid mi

Question 1038897: Suppose we have a 400 liter mixture of acid solution, which is 10% acid, and 90% water. Let V be the number of liters of pure water to add to the mixture so that it is a 8% acid mixture. Find the quantity of water to add. Identity the unknown; write an equation for the unknown; solve the equation; state the answer in a full sentence.
Found 3 solutions by josgarithmetic, MathTherapy, ikleyn:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!

s volume of the initial acid mixture k percent concentration of initial acid mixture V volume of water to add h percent of the acid wanted in the final mixture, percent

Solve for V.
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
Suppose we have a 400 liter mixture of acid solution, which is 10% acid, and 90% water. Let V be the number of liters of pure water to add to the mixture so that it is a 8% acid mixture. Find the quantity of water to add. Identity the unknown; write an equation for the unknown; solve the equation; state the answer in a full sentence.

.1(400) + 0V = .08(400 + V)
Solve this to get:
Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.
Suppose we have a 400 liter mixture of acid solution, which is 10% acid, and 90% water.
Let V be the number of liters of pure water to add to the mixture so that it is a 8% acid mixture.
Find the quantity of water to add.
Identity the unknown; write an equation for the unknown; solve the equation; state the answer in a full sentence.
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See the lesson Mixture problems in this site, Problem 4.

It is your sample. Read it attentively and use it.

See also the associated lessons when you need them.

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