Questions on Algebra: Complex Numbers answered by real tutors!

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Question 151531: Solve the equation by factoring.
6x^2-11x+2
: Solve the equation by factoring.
6x^2-11x+2

Answer by jim_thompson5910(9368) About Me  (Show Source):
You can put this solution on YOUR website!
First, let's factor 6x^2-11x+2





Looking at the expression 6x^2-11x+2, we can see that the first coefficient is 6, the second coefficient is -11, and the last term is 2.


Now multiply the first coefficient 6 by the last term 2 to get (6)(2)=12.


Now the question is: what two whole numbers multiply to 12 (the previous product) and add to the second coefficient -11?


To find these two numbers, we need to list all of the factors of 12 (the previous product).


Factors of 12:
1,2,3,4,6,12
-1,-2,-3,-4,-6,-12


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to 12.
1*12
2*6
3*4
(-1)*(-12)
(-2)*(-6)
(-3)*(-4)

Now let's add up each pair of factors to see if one pair adds to the middle coefficient -11:


First NumberSecond NumberSum
1121+12=13
262+6=8
343+4=7
-1-12-1+(-12)=-13
-2-6-2+(-6)=-8
-3-4-3+(-4)=-7



From the table, we can see that there are no pairs of numbers which add to -11. So 6x^2-11x+2 cannot be factored.



Are you sure that the book asked you to factor 6x^2-11x+2? I would double check the problem.