Questions on Algebra: Complex Numbers answered by real tutors!

Algebra ->  Algebra  -> Complex Numbers Imaginary Numbers Solvers and Lesson  -> Lesson -> Questions on Algebra: Complex Numbers answered by real tutors!     (Log On)
Ad: Algebra Solved!™: algebra software that solves YOUR algebra homework problems with step-by-step help!

   

Question 144510: Multipy or divide as indicated. Simplify completely.
(48x+48 / 10x-4)(40x-16 / 12x^2-12)
In other words, 48x+48 over 10x-4 multiplied by 40x-16 over 12x^2-12: Multipy or divide as indicated. Simplify completely.
(48x+48 / 10x-4)(40x-16 / 12x^2-12)
In other words, 48x+48 over 10x-4 multiplied by 40x-16 over 12x^2-12
Answer by ankor@dixie-net.com(4535) About Me  (Show Source):
You can put this solution on YOUR website!
(48x+48)/(10x-4) * (40x-16)/(12x^2-12)
:
we can do some major factoring here:
(48(x+1))/(2(5x-2)) * (8(5x-2))/(12(x^2-1))
:
Note that (x^2-1) can be factored as the "difference of squares"
(48(x+1))/(2(5x-2)) * (8(5x-2))/(12(x-1)(x+1))
;
Cancel the numbers first and you have:
(24(x+1))/((5x-2)) * (2(5x-2))/(3(x-1)(x+1))
then 3 into 24
(8(x+1))/((5x-2)) * (2(5x-2))/((x-1)(x+1))
:
Cancel (x+1) and (5x-2)
8 * 2/((x-1)) = 16/(x-1)
:
How about this? did it make sense to you? any questions?