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Tutors Answer Your Questions about Complex numbers (FREE)
Question 178761: 18. Let z = a + bi represent a general complex number. As noted in the lesson, the conjugate of z, abbreviated conj(z) or conj(a + bi) is the complex number a-bi. Also, the modulus of z, modulus(z) is the "size" of z, or SQRT(a2 + b2). Which of the following is true for all complex numbers?
A) All of the following
B) z*conj(z) = [modulus(z)]2
C) z + conj(z) = 2a
D) z - conj(z) = 2bi
E) None of the above
19. Using the definition of “size” of z from problem #18, which of the following is largest?
A) 3i
B) -7
C) 4
D) -2i
E) 4 + 4i
FNone of the above
Click here to see answer by solver91311(5072)  |
Question 178955: Can someone please help me with these five question!?!?! Please and thank you sooooooo much!!!
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Click here to see answer by Mathtut(3670)  |
Question 181401: My teacher proved that -1 = 1, homework is to find out what is wrong with the proof. I cant do it. Help, thanks Mick.
-1/1=1/-1
....Take the square root of both sides;-
(-1/1)^.5=(1/-1)^.5
....Take the square root of each term;-
(-1)^.5/(1)^.5=(1)^.5/(-1)^.5
....Sq Root -1 = i Sq Root 1 = 1;-
i/1=1/i
....Cross multiply;-
i^2=1^2
....Sq Root i is -1 and SqRoot 1 is 1;-
-1=1
....QED
Thanks for any help again.
Click here to see answer by solver91311(5072)  |
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