SOLUTION: 1.3+i√5 ________ 3-i√5 2.4-i√2 __________ i√2

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: 1.3+i√5 ________ 3-i√5 2.4-i√2 __________ i√2      Log On


   

Question 179620: 1.3+i√5
________
3-i√5






2.4-i√2
__________
i√2
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
I will do one. and get you started on the other.. you must multiply by the conjugate to get rid of the complex number in the denominator
:
1.3+i√5/3-i√5
:so we have %281.3%2Bi%2Asqrt%285%29%29%2F%283-i%2Asqrt%285%29%29
:
so the conjugate of 3-+sqrt+%285%29 is 3+%2Bi%2Asqrt+%285%29
:

:
%283.9%2B2.3i%2Asqrt%285%29-5%29%2F%289%2B5%29
:
%281.1-2.3i%2Asqrt%285%29%29%2F14
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:
:
2.4-i√2/i√2 the conjugate for this is -i%2Asqrt%282%29 repeat what took place in the problem I just solved...multiplying both top and bottom by the conjugate