SOLUTION: how do you find the discriminant of each quadratic equation then state the number and type of solutions of n^2-14n+9=-11n-4-5n^2?

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Question 174689: how do you find the discriminant of each quadratic equation then state the number and type of solutions of n^2-14n+9=-11n-4-5n^2?
Answer by jim_thompson5910(14933) About Me  (Show Source):
You can put this solution on YOUR website!
n%5E2-14n%2B9=-11n-4-5n%5E2 Start with the given equation.


n%5E2-14n%2B9%2B11n%2B4%2B5n%5E2=0 Get all terms to the left side.


6n%5E2-3n%2B13=0 Combine like terms.

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From 6n%5E2-3n%2B13 we can see that a=6, b=-3, and c=13


D=b%5E2-4ac Start with the discriminant formula.


D=%28-3%29%5E2-4%286%29%2813%29 Plug in a=6, b=-3, and c=13


D=9-4%286%29%2813%29 Square -3 to get 9


D=9-312 Multiply 4%286%29%2813%29 to get %2824%29%2813%29=312


D=-303 Subtract 312 from 9 to get -303


Since the discriminant is less than zero, this means that there are two complex solutions. In other words, there are no real solutions.