You can
put this solution on YOUR website!
7/(3-5i) First, we'll multiply the numerator and denominator by the conjugate of 3-5i which is 3+5i. This will get rid of the radical in the denominator.
(7(3+5i))/((3-5i)(3+5i)) =
(7(3+5i))/(9-25(i^2)) but i^2 is -1, so
(7(3+5i))/(9+25)=
7(3+5i)/34
Hope this helps---ptaylor
