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Tutors Answer Your Questions about Complex Numbers (FREE)
Question 6598: Dear Sir/Madam,
I am confronted with the following problem:
"Solve for x. Find all solutions. x^3 + 2x^2 + 5x = 0"
I did the following:
1) x(x^2 + 2x + 5 = 0)
2) x = 0
3) x^2 + 2x + 5 = 0
4) 
5) , which gives you a non-real answer.
So I assumed that the only answer is x = 0, however the answer is x = 0, -1+-2i. What is meant by 2i? Does i stand for imaginary number? And how do you get that answer?
Thanks in advance.
Regards,
-Mike
Click here to see answer by ichudov(404)  |
Question 7120: ( Evaluate each expression for the given values of the variables)
3(2c+d)-d; c=5 and d=1
3(2+5+1)-d
I dont understand the second step if i do what is in the parenthese first then distrubute or distrubute first? i just cant get past the second step.
Click here to see answer by glabow(165)  |
Question 8200: Could someone please help me out with this one? I am suppose to evaluate this expression if a= -2, b = 5, c = -4, and d = 6
b^2 - 2bc+c^2 =
Here is what I have tried but it really looks wrong to me.
5^ - 2(5)(-4)+ -4^2 = and now I can't even figure out the answer to this. So I know there has to be a better way and I am hoping someone can show me.
Thanks
Click here to see answer by AnlytcPhil(958)  |
Question 8271: please help me solve this equation..... 16.5d-(d+3)=(d+2)+7
20.6(x+2)=4-(3-2x)=1 24.2(x+1)+15x=-(3x-17)+5x 28.8y-3(4-2y)=6(y+1)-2 32.-4(2x-5)+3x=x-28 36.-4(2x-5)+3x=x+x-28 40. 7-24-3x+8x=-(x+31)
Click here to see answer by bonster(299)  |
Question 8979: Hi
I am having trouble solving the following problem:
x^3-8=0
Can you provide some help in solving this - there are three answers one of which is 2 but I cannot figure out the other two imaginary ones.
Thanks
Lee
Click here to see answer by rapaljer(3613)  |
Question 10086: Could you explain the steps of how to solve this? I understand negative cube root of the -27 is -3 and that I should factor sqrt -27 into sqrt 9 and sqrt 3, where do I go from here? Thank You
Please express in the form of "a + bi."
negative cube root -27 + sqrt -27
Click here to see answer by rapaljer(3613)  |
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