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Tutors Answer Your Questions about Complex Numbers (FREE)
Question 1784: so I can get a answer using complex numbers I am taking Intermediae Algerbra in college and my final is in the moring. I got as far as the answer you gave me but the answer my teacher gave me 2+i and 2-i. I am confused as how she got that answer by using the qudratic equation using (Imagery Solution). Thank you so much I have been struggling over this problem all weekend.
Click here to see answer by longjonsilver(2297)  |
Question 4632: i^91=?
This question was asked previously (question 3340), and the given soluttion was to find where i^91 came in the cycle of i. However I learned another way to do it, and I was wondering if it is correct.
Take the given question i^91:
i^91 = i^90 + 1
= i^90 * i^1
= (i^2)^45*i^1
= -1^45 * i^1
= -1 * i
= -i
Click here to see answer by longjonsilver(2297)  |
Question 4632: i^91=?
This question was asked previously (question 3340), and the given soluttion was to find where i^91 came in the cycle of i. However I learned another way to do it, and I was wondering if it is correct.
Take the given question i^91:
i^91 = i^90 + 1
= i^90 * i^1
= (i^2)^45*i^1
= -1^45 * i^1
= -1 * i
= -i
Click here to see answer by khwang(438)  |
Question 4786: Hello...
I am having some trouble with a proof. I am to use:
(a + bi)(a - bi)
The problem asks:
Show that for a + bi not equal to 0 this product is a positive real number.
Thanks for your help.
Click here to see answer by ichudov(404)  |
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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980
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