SOLUTION: (3-2i)(1+i) + |3+4i|. Turn this into a+bi form

Algebra.Com
Question 990393: (3-2i)(1+i) + |3+4i|.
Turn this into a+bi form

Answer by ikleyn(52754)   (Show Source): You can put this solution on YOUR website!
.
1.  Let me calculate this term first,  (3-2i)(1+i).

You need simply open parentheses,  make multiplications,  collect common terms and use the fact that  i*i = = -1.  So,
= = = 3 + i -2*(-1) = 3 + i + 2 = 5 + i.

Very good.

2.  Now let consider this term,  |3 + 4i|.

It is the modulus of the complex number  3 + 4i.
As you probably know,  the modulus is the square root of the sum of squares of the components:  r = = = = 5.

So,  the modulus  r  is,  in our case,  simply the real number  5.

Very good.

3.  Now,  the sum (3-2i)(1+i) + |3 + 4i| = (5 + i) + 5 = 10 + i.

That is all.

Congratulations!

To learn more on complex numbers, you can read my lessons in this site
Complex numbers and arithmetic operations on them
Complex plane
Addition and subtraction of complex numbers in complex plane
Multiplication and division of complex numbers in complex plane
Raising a complex number to an integer power
How to take a root of a complex number
Solution of the quadratic equation with real coefficients on complex domain
How to take a square root of a complex number
Solution of the quadratic equation with complex coefficients on complex domain

It is free of charge.


RELATED QUESTIONS

Compute the following and simplify in the form a+bi... (answered by stanbon)
write expression 4i^3-2i^2+1 in standard form a+bi (answered by jim_thompson5910)
2-i/3+4i in a +- bi... (answered by Alan3354)
Select any imaginary number (of the form "a + bi" where a and b are non-zero real... (answered by jim_thompson5910)
Write each expression in the form a + bi. 1. 2i(i^(-3)) 2. 2i(i^(-3)) รท... (answered by MathLover1)
Evaluate the expression and write the result in the form a + bi. 1/(2-4i)-1/(6-2i) (answered by stanbon)
(3+4i)(1-2i) (answered by richwmiller,MathTherapy)
How do you simplify ((1-2i)/(3+i)) and write in a+bi... (answered by prince_abubu)
(1+2i)/(3-4i)+(2-i)/5i (answered by MathLover1,Alan3354)