SOLUTION: How would I use DeMoiver's Theorem to find 2 square roots of 16(cos330 + j sin330)in polar form?

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Question 986069: How would I use DeMoiver's Theorem to find 2 square roots of 16(cos330 + j sin330)in polar form?
Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
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See the lesson  How to take a root of a complex number  in this site.

Answer.  One root is    = 4*(cos(115°) + i*sin(115°))     (notice that  115° = .330°).

              The other root is    = 4*(cos(115°+180°) + i*sin(115°+180°)) = 4*(cos(295°) + i*sin(295°)).     (Notice that  180° = .360°).

              Also notice that = .


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