SOLUTION: solve in complex number system. x^2-4x+9=0. x to the 2nd power minus 4x plus 9 equals 0
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Question 980627: solve in complex number system. x^2-4x+9=0. x to the 2nd power minus 4x plus 9 equals 0
Found 2 solutions by Boreal, josh_jordan:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
quadratic formula
(1/2a){-b +/- sqrt (b^2-4ac)}
(1/2) {4 +/- sqrt (16-36)} sqrt (-20)= 2i sqrt (5), because it is sqrt (-4)*sqrt (5)
x=(1/2){ 4+/- 2i sqrt (5)}
x=2 +/- i sqrt (5)
Answer by josh_jordan(263) (Show Source): You can put this solution on YOUR website!
Because we are dealing with complex numbers, we will need to use the quadratic formula, where a = 1, b = -4, and c = 9, and substitute the letters with the numbers represented by them:
----->
----->
----->
Next, factor extract a 2 out of the equation to get rid of the two in our denominator:
----->
, which is our final answer
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