SOLUTION: 1. Use calculus to find the absolute minimum of f(x) = x^2 � 6x + 2 2. Evaluate two different ways: lim (x^2 � 16) / (x -4) where x -> 4 3. Where is f(x) = -sin x + cos

Question 979130: 1. Use calculus to find the absolute minimum of f(x) = x^2 � 6x + 2
2. Evaluate two different ways: lim (x^2 � 16) / (x -4) where x -> 4
3. Where is f(x) = -sin x + cos x concave up on [0, 2π] (it may help to consider graphs)
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
1. Find the derivative.

Set it equal to zero.

So when ,

Since the second derivative, , the extrema at is a minimum.
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.
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2. - Removable discontinuity.
- L'Hopital's Rule
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.
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3. Function in red, second derivative is in purple.
Function (red) is concave up when the second derivative (purple) is greater than zero.

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