You can
put this solution on YOUR website!2+3i, 4+3i,in form r(cosQ^+isinQ)
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Forms:
a+bi can be converted using the following:
r= sqrt(a^2+b2)
Q = tan^-1(b/a)
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Your Problems
2+3i converts as follows:
r = sqrt(2^2+3^2) = sqrt(13)
Q = tan^1(3/2) = 56.3 degrees
2+3i = (sqrt(13))(cos(56.3)+isin(56.3))
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4+3i converts as follows:
r = sqrt(4^2+3^2)=sqrt(25) = 5
Q = tan^-1(3/4) = 36.87 degrees
4+3i = 5(cos(36.87)+isin(36.87))
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Cheers,
Stan H.
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