SOLUTION: For any integer "n", find i^(4n+a) when "a" takes on the following values. 3 & 2 Please show all work-- I don't understand this type of problem

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Question 945634: For any integer "n", find i^(4n+a) when "a" takes on the following values.
3 & 2
Please show all work-- I don't understand this type of problem
Answer by richard1234(7193)   (Show Source): You can put this solution on YOUR website!
Hint: i^1 = i, i^2 = -1, i^3 = -i, i^4 = 1 and it repeats.

Also, i^(4n+a) = i^(4n)i^a = i^a

Now just plug in a = 2, 3.
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