SOLUTION: g(x)=-x^2+x-5

Algebra.Com
Question 9278: g(x)=-x^2+x-5
Answer by rapaljer(4671)   (Show Source): You can put this solution on YOUR website!
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

The discriminant -19 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.


In the field of imaginary numbers, the square root of -19 is + or - .

The solution is

Here's your graph:
RELATED QUESTIONS

g(x)=5^x;find... (answered by poliphob3.14)
g(x)=2/x+5 (answered by tommyt3rd)
G(x)=... (answered by Alan3354)
g(x)=... (answered by Fombitz)
g... (answered by ikleyn,Shin123)
what is g(2)? when g(x)=5+x... (answered by Earlsdon)
if g(x)=x^2-5, find: g(0.5) (answered by haileytucki)
f+g and f-g f(x)7x^2+5 g(x)x^2-13 (answered by nycsub_teacher)
g(x)=2^x show: g(x+1) =... (answered by fcabanski)