SOLUTION: How would I solve the problem "(7i)(-6i)(4-8i)"?
Algebra.Com
Question 893714: How would I solve the problem "(7i)(-6i)(4-8i)"?
Found 2 solutions by Alan3354, josgarithmetic:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Multiply the 1st 2 terms, then multiply by the 3rd term.
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
You would use the same as what you already learned.
RELATED QUESTIONS
How would I write the following expressions as complex numbers in standard form?
-i(4 -... (answered by harpazo)
Standard form
(3-8i) - (5-6i)
*Also...
10i... (answered by tommyt3rd)
1. (-2-2)(-4-3i)(7+8i)
2. 5i+7i*i
3. (6i)^3
4. 6i*-4i+8
5. -6(4-6i)
6. (8-3i)^2
7.... (answered by harpazo)
how to solve... (answered by Alan3354)
Directions: Simplify the following-
1. 7i^5-8i^4+5i^3-4i^2
2.... (answered by MathLover1)
(1+8i)+(6i)=(i) (answered by Fombitz)
(4-6i)(7+8i) (answered by flame8855)
Dividing Complex numbers: The question:
(5-6i)(4+7i)/(2+i)(5-6i) I tried multiplying... (answered by solver91311)
(2-4i)(-6+4i)
(-3+2i)(-6-8i)
(8-6i)(-4-4i)
(1-7i)squared
6(-7+6i)(-4+2i) (answered by Alan3354)