SOLUTION: Solve: {{{x^2-2x-15<0}}}

Algebra.Com
Question 882939: Solve:
Found 2 solutions by LinnW, MathTherapy:
Answer by LinnW(1048)   (Show Source): You can put this solution on YOUR website!

first solve


x = 5 or x = -2
So for values of x between -2 and 5,
x^2-2x-15 is less than zero
(-2,5) is our solution
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
Solve: 




 ---- Changing inequality to equality to determine CRITICAL POINTS.

(x + 3)(x - 5) = 0

Critical points: 

Test intervals:  x < - 3, , and x > 5

ONLY  proves TRUE. 

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