SOLUTION: How would I write the following expressions as complex numbers in standard form? -i(4 - 8i) (5 - 7i)(-4 - 3i) 6i/3 - i -2 - 5i/3i

Algebra.Com
Question 877094: How would I write the following expressions as complex numbers in standard form?
-i(4 - 8i)
(5 - 7i)(-4 - 3i)
6i/3 - i
-2 - 5i/3i

Answer by harpazo(655)   (Show Source): You can put this solution on YOUR website!
The standard form looks like
a + bi.
Post one question at a time or else no one will reply.
I will do (5 - 7i)(-4 - 3i).
Use FOIL method to expand.
5(-4) = -20
5(3i) = 15i
(-7i)(-4) = -28i
(-7i)(-3i) = 21i^2
We have -20+15i-28i+21i^2.
Remember i^2 = -1
-20-13i+21(-1)
-20-13i-21
Answer: -41-13i

RELATED QUESTIONS

how would I write the following expression as complex numbers in standard form? -2-5i/3i (answered by tommyt3rd)
I need help solving these problems with complex numbers write the sum as a complex... (answered by Prithwis)
Directions: Simplify the following- 1. 7i^5-8i^4+5i^3-4i^2 2.... (answered by MathLover1)
1. (-2-2)(-4-3i)(7+8i) 2. 5i+7i*i 3. (6i)^3 4. 6i*-4i+8 5. -6(4-6i) 6. (8-3i)^2 7.... (answered by harpazo)
Write the expression as a complex number in standard form. 2i-(2+3i)+(1-8i) When... (answered by scott8148)
i have many questions what is the answers to these problems when u divide complex... (answered by josmiceli)
5-3i+4+zi I(2+3i) (4-5i)(4+5i) (4+7i)-(2-5i) Solve the equation in complex... (answered by ikleyn,Alan3354)
write the expression as a complex number in standard form... (answered by mouk)
Write in standard form:... (answered by jim_thompson5910)