SOLUTION: hi good day how do i find the critical numbers of y=3x^3-12x^2-7 to perform the derivative test and please show me how to factor it cause i have no ideal how to do it

SOLUTION: hi good day how do i find the critical numbers of y=3x^3-12x^2-7 to perform the derivative test and please show me how to factor it cause i have no ideal how to do it

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Question 875141: hi good day how do i find the critical numbers of y=3x^3-12x^2-7 to perform the derivative test and please show me how to factor it cause i have no ideal how to do it
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
critical numbers of y=3x^3-12x^2-7
.
begin by finding the y'
y=3x^3-12x^2-7
y'=9x^2-24x
.
Set y' to zero and solve for x to find critical points:
0=9x^2-24x
0=(3x)(3x-8)
x = {0, 8/3} (critical points)

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