SOLUTION: Please help me solve this problem: Find all complex square roots of i. in other words find all complex solutions of x^2 = i

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Question 857211: Please help me solve this problem:
Find all complex square roots of i. in other words find all complex solutions of x^2 = i

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
This may be only part of the answer, but x%5E2=i if x=cos%28pi%2F4%29%2Bi%2Asin%28pi%2F4%29.

How?
Draw a unit circle. The horizontal axis is Real and the vertical axis is Imaginary. Horizontal intercepts are 1 and -1. Vertical intercepts are i and -i. Think of multiplications by whole number powers of i to be rotations starting at (1,0). If 1*1, get 1. If 1*-1, get -1. If 1*i, get i. If 1*(i)(i), get same as 1*(-1) which is -1. Thinking this way, the way to go from negative 1 to HALF WAY from negative 1 to positive 1 is the take square root of -1.

In that same way, if you start with x%5E2=i, and you want what is x, this is like starting at (0,i) on this complex unit circle, and rotating half-way from (0,i) to (1,0). This puts your point on an angle of positive pi%2F4. The coordinates on this point are as (cos(pi/4),i*sin(pi/4)), which you can represent as highlight%28cos%28pi%2F4%29%2Bi%2Asin%28pi%2F4%29%29.