SOLUTION: Hi. Use the given zero to find the remaining zeros of each function. h(x)=x^4-9x^3+21x^2+21x-130 Zero: 3-2i So I know that we have 2 zeros now: (x-(3-2i)(x-(3+2i).

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Question 853003: Hi. Use the given zero to find the remaining zeros of each function.
h(x)=x^4-9x^3+21x^2+21x-130 Zero: 3-2i
So I know that we have 2 zeros now: (x-(3-2i)(x-(3+2i). But how can I proceed? I don't know how to divide the product of those zeros in a synthetic division.
Many thanks
Found 2 solutions by ewatrrr, richwmiller:
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 

Hi,

h(x)=x^4-9x^3+21x^2+21x-130      

graphing calculator/software or Trial & Error would give the remaining real roots:

  x = -2  and x = 5

FREE graph software available at http://www.padowan.dk.com



 

Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
 (x^2-3x-10)(x^2-6x+13)

x^2-3x-10= (x+2) (x-5)

(x+2)(x-5)(x^2-6x+13)

(x-(3-2i)(x-(3+2i)=(x^2-6x+13)

the zeros must be factors of -130

the prime factors are -2󬊁3

There are only a few to test

-2, 2, -5 and 5 , -13 and 13







 

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