SOLUTION: The question must be answered in trigonometric form: 4i / (-1+ sqrt(3)i) Thank you!

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Question 852727: The question must be answered in trigonometric form:
4i / (-1+ sqrt(3)i)
Thank you!

Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
x%2Biy%22%22=%22%224i+%2F+%28-1%2B+sqrt%283%29i%29

First get it in the form x+iy by multiplying numerator
and denominator by the conjugate of the denominator: 

4i%28-1-sqrt%283%29i%29+%2F%28%28-1%2B+sqrt%283%29i%29%28-1-+sqrt%283%29i%29%29

%28-4i-4sqrt%283%29i%5E2%29%2F%281-3i%5E2%29

Change both iČ's to (-1):

%28-4i-4sqrt%283%29%28-1%29%29%2F%281-3%28-1%29%29

%28-4i%2B4sqrt%283%29%29%29%2F%281%2B3%29

Factor 4 out of the numerator:

%284%28-i%2Bsqrt%283%29%29%29%2F4

%28cross%284%29%28-i%2Bsqrt%283%29%29%29%2Fcross%284%29

-i%2Bsqrt%283%29

sqrt%283%29-i

So the rectangular form is: 

x%2Biy%22%22=%22%22sqrt%283%29-1

That is represented by the vector (line) connecting the origin to the point 
(x,y)= (sqrt%283%29,-1), We draw a perpendicular to the x-axis, and indicate
the angle theta by a red arc:



We find the value of r (the hypotenuse) by the Pythagorean theorem:

r%5E2%22%22=%22%22x%5E2%2By%5E2

r%5E2%22%22=%22%22%28sqrt%283%29%29%5E2%2B%28-1%29%5E2

r%5E2%22%22=%22%223%2B1

r%5E2%22%22=%22%224

r is always positive so we take the positive square root:

r%22%22=%22%222


We find theta by using any trig function, say the cosine;
cos(theta)=adjacent/hypotenuse=x/r=sqrt(3)/2}}}

This tells us that the angle has a refence angle of 30°, but since
it is in quadrant IV, we subtract from 360° and get theta=%22330%B0%22

r%22%22=%22%222


Next we know that

adjacent%2Fhypotenuse=x%2Fr=cos%28theta%29, so x=r%2Acos%28theta%29=2%2Acos%28%22330%B0%22%29

Also, we know that

opposite%2Fhypotenuse=y%2Fr=sin%28theta%29, so y=r%2Asin%28theta%29=+2%2Asin%28%22330%B0%22%29

So 

x + iy = 2·cos(330°)+i·2·sin(330°) = 2[cos(330°) + i·sin(330°)]

Edwin