Question 824272: can anyone help? -->find the zeros of the equation −3x^2+27x^2+1200=0
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! ---
-3x^2 + 27x^2 + 1200 = 0
-24x^2 + 1200 = 0
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the above quadratic equation is in standard form, with a=-24, b=0, and c=1200
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
-24 0 1200
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
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this quadratic has two real roots (the x-intercepts), which are:
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answer:
x = -7.07106781
x = 7.07106781
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