SOLUTION: I'm having some trouble with a question on my test: . -11x^2+12x - 6 = 0 . Answers: . A) x ={-6 +- i[SQRT(60)]}/11 B) x = {-6 +- i[SQRT(30)]}/-11 C) x = {6 +- i[SQRT(12)]

Question 744694: I'm having some trouble with a question on my test:
.
-11x^2+12x - 6 = 0
.
Answers:
.
A) x ={-6 +- i[SQRT(60)]}/11
B) x = {-6 +- i[SQRT(30)]}/-11
C) x = {6 +- i[SQRT(12)]}/6
D) x = {-6 +- i[SQRT(22)]}/-11
E) x = {-11 +- i} /6
F) x = {11 +- i} /-6
.
.
What I did first is to insert the question into the quadratic formula, with -11, 12 and -6 as a, b and c.
(-12 � √144 - 264) / (-22)
Which turns into
(-12�√-120) / -22
.
But now I'm stuck. Could I have some help please?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
-11x^2+12x - 6 = 0
.
Answers:
.
A) x ={-6 +- i[SQRT(60)]}/11
B) x = {-6 +- i[SQRT(30)]}/-11
C) x = {6 +- i[SQRT(12)]}/6
D) x = {-6 +- i[SQRT(22)]}/-11
E) x = {-11 +- i} /6
F) x = {11 +- i} /-6
.
.
What I did first is to insert the question into the quadratic formula, with -11, 12 and -6 as a, b and c.
(-12 � √144 - 264) / (-22)
Which turns into
(-12�√-120) / -22
.
But now I'm stuck. Could I have some help please?
-----------------------
(-12�√-120) / -22 You were almost done.
=
=
--> C
============

Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

The discriminant -120 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.

In the field of imaginary numbers, the square root of -120 is + or - .

The solution is , or
Here's your graph:

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