SOLUTION: Find the equation of the tangent line for f(x)=3x^2-x at the given point (-2,14)

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Question 743739: Find the equation of the tangent line for f(x)=3x^2-x at the given point (-2,14)
Answer by tommyt3rd(5050)   (Show Source): You can put this solution on YOUR website!
f' = 6x-1
f'(-2)=6(-2)-1=-13

so m=-13
y-b=m(x-a)
y-14=-13(x--2)
y-14=-13(x+2)

:)

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