SOLUTION: I need some help with this question -4 1/5x2 + 1 2/5x - 2 4/5 = 0 Here are my options. I can't seem to get it right. A) x = {1 +- i[SQRT(23)]}/6 B) x = {-1 +- i[SQRT(10)

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Question 743616: I need some help with this question
-4 1/5x2 + 1 2/5x - 2 4/5 = 0
Here are my options. I can't seem to get it right.
A) x = {1 +- i[SQRT(23)]}/6
B) x = {-1 +- i[SQRT(10)]} / 6
C) x = {1 +- [SQRT(23)]} /-6
D) x = 1 +- 5/2 x^2
E) x = -1 +- 2/5 x^2
F) x = 2 +- 20 x^2
Answer by Edwin McCravy(20060)   (Show Source): You can put this solution on YOUR website!
x² + x -  = 0

Change the mixed fractions to improper fractions:

x² + x -  = 0

Clear of fractions by multiplying every term through by 5

-21x² + 7x - 14 = 0

Divide through by -7, (negative so the leading term will be 
positive):

3x² - x + 2 = 0

That doesn't factor so we use the quadratic formula:

x = 

with a = 3, b = -1, c = 2

x = 

x = 

x = 

x = 

x = 

Edwin
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