SOLUTION: What are 4'th roots of -8i
Algebra.Com
Question 740801: What are 4'th roots of -8i
Answer by tommyt3rd(5050) (Show Source): You can put this solution on YOUR website!
-8i = 8 at 270 deg
n=4
k=0,1,2,3
k=0:
r= 4-th-root(8)at theta=(270)/4=135/2
k=1:
r=4-th-root(8) at theta=(270+360)/4=315/2
k=2:
r=4-th-root(8) at theta=(270+720)/4=495/2
k=3:
r=4-th-root(8) at theta=(270+1080)/4=675/2
:)
RELATED QUESTIONS
Find the polynomial of lowest degree whose roots are 2i and... (answered by richard1234)
What are three cube roots of -8i in rectangular coordinates? Question asks to give exact... (answered by Alan3354)
(4+8i)(4-8i) (answered by ewatrrr)
What are the roots of |9x^2 - 4| = x +... (answered by josgarithmetic)
what is (-4-8i) (3+i) please solve... (answered by Fombitz)
(9-4i)(4+8i) (answered by stanbon)
(-4-8i)(3+i) (answered by jim_thompson5910)
(4-3i)-(7+8i) (answered by stanbon)
(4-6i)(7+8i) (answered by flame8855)