SOLUTION: Hello,The problem looks like this... Solve the equation; find all solutions, including complex solutions: x^3 + 5x + 4 = 4(x^2 + 1) I've tried to take the right side of the e

Question 730066: Hello,The problem looks like this...
Solve the equation; find all solutions, including complex solutions:
x^3 + 5x + 4 = 4(x^2 + 1)
I've tried to take the right side of the equation and distribute the 4, then subtracting the individual terms from the left side leaving me with
x^3 - 4x^2 + 5x = 0 Then I tried to factor out x from the right side
x(x^2 -4^x + 5) = 0 I cant do much more because of the sign in front of the 4 being (-) and the sign in front of 5 being +.
So I tried using imaginary numbers on the right side leaving me with....
x^3 + 5x +4 = (2x + 2i)(2x - 2i)
and now im stuck confused and irritated. I don't know if I'm doing any of the step work correctly.
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
x(x^2 -4^x + 5) = 0
x = 2+i
x = 2-i
x=0

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