SOLUTION: What is the stes to find the values of x and y where x and y are real numbers (3x-4)+((5/3)yi=-6+5i

Question 719870: What is the stes to find the values of x and y where x and y are real numbers (3x-4)+((5/3)yi=-6+5i
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!
Two complex numbers in standard a + bi form are equal only if the real parts, the a's are equal the the imaginary parts, the b's are equal.

The real part (the part without any i's) of (3x-4)+((5/3)yi=-6+5i is 3x-4. So this must be equal to -6:
3x-4 = -6
Adding 4:
3x = -2
Divide by 3:
x = -2/3

The imaginary part (the part with the i's) of (3x-4)+((5/3)yi=-6+5i is (5/3)yi. So this must be equal to 5i:
(5/3)yi = 5i
or (5/3)y = 5
Multiplying by 3/5 we get:
y = 3
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