SOLUTION: Three impedances are connected in parallel, Z1 = 2+j2 Z2 = 1+j5 and Z3 = j6 Find the equivalent admittance Y Where: Y= 1/Z1 + 1/Z2 + 1/Z3 Express in both rect

Question 719085: Three impedances are connected in parallel,

Z1 = 2+j2
Z2 = 1+j5 and
Z3 = j6

Find the equivalent admittance Y

Where:

Y= 1/Z1 + 1/Z2 + 1/Z3

Express in both rectangular and polar forms.

I am currently struggling on Z3= j6,but clarification on the rest would be a great help.
Thanks

Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!

Each term can be transformed by multiplying numerator and denominator times the conjugate of the denominator.

is a good common denominator

That can be expressed as
= approximately
Unless your problem is just a math exercise, you would use
which provides enough decimal places for practical purposes.
For the polar form we know that the absolute value would be
r=approximately= approximately
If this was just a math exercise, and an exact value was required,

The angle would be such that
= approximately
That corresponds to approximately
in radians or
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