SOLUTION: Ok so I have a problem. The question is:
Find the values of x and y for which each equation is true.
3x-5yi = 15-20i
In this situation i= the imaginary number. A friend of m
Algebra.Com
Question 70901: Ok so I have a problem. The question is:
Find the values of x and y for which each equation is true.
3x-5yi = 15-20i
In this situation i= the imaginary number. A friend of mine suggested that I square both sides and try to solve for x. I did this but the answer I came up with was x = (5(i[square root]7 + y))/3. When I attempted to put this into the problem the answer for y was an equally huge answer that did not make any sense. If you could please help me promptly this would be sooo much help!!!
THANK YOU!!!
Algebra_2_4U
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
3x-5yi = 15-20i
---------
Equate the Real parts to get 3x=15; then x=5
Equate the Imaginary parts to get -5y=-20; then y=4
Answer: x=5 and y=4
Cheers,
Stan H.
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