SOLUTION: can you help me solve: [(-b^(-2))(c)]^0 / [8(a^(-1))(c^2)]
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Question 70618
:
can you help me solve: [(-b^(-2))(c)]^0 / [8(a^(-1))(c^2)]
Answer by
ankor@dixie-net.com(12692)
(
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You can
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[(-b^(-2))(c)]^0 / [8(a^(-1))(c^2)]
:
Assume you mean:
:
Any number or expression to 0 power is 1 so we have:
:
An exponent of -1 means the reciprocal so we have: