SOLUTION: directions: Solve over the complex number system. (i do not know what this means.) 2x^2-4x+5=0 thank you for taking the time to look at this

Algebra ->  Algebra  -> Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: directions: Solve over the complex number system. (i do not know what this means.) 2x^2-4x+5=0 thank you for taking the time to look at this       Log On

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Question 6841: directions: Solve over the complex number system.
(i do not know what this means.)
2x^2-4x+5=0

thank you for taking the time to look at this
problem.
Found 2 solutions by longjonsilver, glabow:
Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
solve it using the quadratic formula.

the answer you get is %284%2B-+sqrt%28-24%29%29%2F%284%29 which is %284%2B-+%282sqrt%283%29%29i%29%2F%284%29

jon.

Answer by glabow(165) About Me  (Show Source):
You can put this solution on YOUR website!
I get the following, using the quadratic equation:
x+=+%284+%2B-+sqrt%2816-40%29%29%2F4
x+=+%284+%2B-+sqrt%28-24%29%29%2F4
x+=+%284+%2B-+sqrt%28-4%286%29%29%29%2F4
x+=+%284+%2B-+2i%28sqrt%286%29%29%29%2F4
x+=+1+%2B-+%281%2F2%29i%28sqrt%286%29%29
Checking: for x=1%2B%281%2F2%29i%28sqrt%286%29%29
x%5E2=1%2Bi%28sqrt%286%29%29-%286%2F4%29
2x%5E2=2%2B2i%28sqrt%286%29%29-3
-4x=-4-2i%28sqrt%286%29%29
x%5E2-4x%2B5=2%2B2i%28sqrt%286%29%29-3-4-2i%28sqrt%286%29%29%2B5=0