# SOLUTION: directions: Solve over the complex number system. (i do not know what this means.) 2x^2-4x+5=0 thank you for taking the time to look at this

Algebra ->  Algebra  -> Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: directions: Solve over the complex number system. (i do not know what this means.) 2x^2-4x+5=0 thank you for taking the time to look at this       Log On

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 Algebra: Complex Numbers Solvers Lessons Answers archive Quiz In Depth

 Question 6841: directions: Solve over the complex number system. (i do not know what this means.) 2x^2-4x+5=0 thank you for taking the time to look at this problem.Found 2 solutions by longjonsilver, glabow:Answer by longjonsilver(2297)   (Show Source): You can put this solution on YOUR website!solve it using the quadratic formula. the answer you get is which is jon. Answer by glabow(165)   (Show Source): You can put this solution on YOUR website!I get the following, using the quadratic equation: Checking: for