SOLUTION: how to do these equations (-4+3i)+(6-10i) (1-4i)-(-3+5i) (-2+3i)*(4-8i) (-1+2i)/(-3+4i)

Question 67022: how to do these equations
(-4+3i)+(6-10i)
(1-4i)-(-3+5i)
(-2+3i)*(4-8i)
(-1+2i)/(-3+4i)
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
how to do these equations
(-4+3i)+(6-10i)
ADD/SUBTRACT IMAGINARY NUMBERS WITH 'I'S AND REAL NUMBERS WITHOUT 'I'S SEPARATELY
=(-4+6)+I(3-10)=2-7I
(1-4i)-(-3+5i)
=(1+3)+I(-4-5)=4-9I
(-2+3i)*(4-8i)
[-2*4]+[-2*(-8)+(3)(4)]I+(3)(-8)I^2..............I^2=-1...HENCE
[-8+24]+I[16+12]=16+28I

(-1+2i)/(-3+4i).........MULTIPLY AND DIVIDE WITH -3-4I
[(-1+2I)(-3-4I)]/[(-3+4I)(-3-4I)]
=(3-2I-8I^2)/(9-16I^2)
=(11-2I)/(25)
RELATED QUESTIONS
I'm on algebra 2 and need help with my work please. It says find the value of the complex (answered by richwmiller)

How do I solve complex number problems like 6+5i/-2i, 2/7-8i, 3-i/2-i, and... (answered by Fombitz)

i have many questions what is the answers to these problems when u divide complex... (answered by josmiceli)

1. (-2-2)(-4-3i)(7+8i) 2. 5i+7i*i 3. (6i)^3 4. 6i*-4i+8 5. -6(4-6i) 6. (8-3i)^2 7.... (answered by harpazo)

I wanted you to check my answers on these two problems: 1) Problem: (2-4i)(2-i)... (answered by checkley77,gonzo)

simplify... (answered by ikleyn)

Hello. My son is struggling with complex numbers and this stuff is like a second language (answered by stanbon,MathLover1)

(3-71)(3+7i) (2-2i)(2+2i) (7-10i)(7+10i) (2+5i)(2-5i) (4+3i)(1-i) (5-7i)(1+2i)... (answered by ewatrrr)

(2-4i)(-6+4i) (-3+2i)(-6-8i) (8-6i)(-4-4i) (1-7i)squared 6(-7+6i)(-4+2i) (answered by Alan3354)