SOLUTION: write the expression as a complex number in Standard form (6i)(3+2i)(1-i)

Question 668475: write the expression as a complex number in Standard form (6i)(3+2i)(1-i)
Answer by ReadingBoosters(3246) (Show Source): You can put this solution on YOUR website!
(6i)(3+2i)(1-i)
...
6i(3+2i) = 18i + 12i^2
i^2 = = -1
18i + 12(-1)
18i - 12
...
(18i-12)(1-i)
18i - 18i^2 - 12 + 12i
30i - 18i^2 - 12
30i - 18(-1) - 12
30i + 18 - 12

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