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The expression: 2+i/3+i is equivalent to?
First multiply the numerator and denominator by 3-i, the conjugate of 3+i. Now we are multiplying by(3-i)/(3-i) which equals 1
((2+i)(3-i))/((3+i)(3-i)) and this equals:
(6+3i-2i-i^2)/(9+3i-3i-i^2) and this equals:
(7+i)/10 which is d)
Hope this helps---ptaylor