SOLUTION: The conjugate of 5 + 6i is
Find the product (2 + i)(3 + 4i). Give your answer in the usual a + bi form
Write the complex number i 15 in the usual a + bi form
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Question 65147: The conjugate of 5 + 6i is
Find the product (2 + i)(3 + 4i). Give your answer in the usual a + bi form
Write the complex number i 15 in the usual a + bi form
Find the reciprocal of the complex number 3 + 2i . Give your answer in the usual a + bi form.
Write the complex number in the usual a + bi form.
What are the coordinates of the complex number -i when we plot it in the complex plane?
Find the magnitude of the complex number 3 - 7i. (In other words, find | 3 - 7i | )
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The conjugate of 5 + 6i is 5-6i
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Find the product (2 + i)(3 + 4i). Give your answer in the usual a + bi form
Use FOIL:
F:2*3=6
O:2*4i=8i
I:3*i=3i
L:i*4i=-4
Combine to get:2+11i
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Write the complex number i 15 in the usual a + bi form
0+15i
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Find the reciprocal of the complex number 3 + 2i . Give your answer in the usual a + bi form.
1/(3+2i)=[3-2i)}/[3+2i)(3-2i)]=[ 3-2i]/[13]=(3/13)-(2/13)i
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What are the coordinates of the complex number -i when we plot it in the complex plane?
(0,-1)
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Find the magnitude of the complex number 3 - 7i. (In other words, find | 3 - 7i | )
|3-7i|=sqrt(9+49)=sqrt58
Cheers,
Stan H.
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