SOLUTION: please help reduce 64y^3+27z^3 / 4y+3z

Question 63567: please help
reduce 64y^3+27z^3 / 4y+3z
Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
reduce [64y^3+27z^3] / [4y+3z]
The numerator is the sum of cubes (4y)^3 + (3z)^3 and is
divisible by 4y+3z leaving a quotient of:
=[(4y)^2-(4y)(3z)+(3z)^2
=16y^2-12yz+9z^2
---------
Cheers,
Stan H.
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!

a = 4y
b = 3z
The equation is now in the form

If you do the long division, this equals
or

answer
You can check this by doing
*
and seeing if it equals
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