SOLUTION: the figure shows ABCD as a trapezium in which AB=(5x+6) cm, DC= 3x cm and the height between the parallel line is (4x-3) cm. Show that the area of the trapezium can be expressed as

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Question 627536: the figure shows ABCD as a trapezium in which AB=(5x+6) cm, DC= 3x cm and the height between the parallel line is (4x-3) cm. Show that the area of the trapezium can be expressed as (16x^2 - 9) cm2
Found 2 solutions by math175, ikleyn:
Answer by math175(1)   (Show Source): You can put this solution on YOUR website!
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Answer by ikleyn(52858)   (Show Source): You can put this solution on YOUR website!
.
the figure shows ABCD as a trapezium in which AB=(5x+6) cm, DC= 3x cm and the height between the parallel line is (4x-3) cm.
Show that the area of the trapezium can be expressed as (16x^2 - 9) cm2
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ 

The area of a trapezoid (of any trapezoid) is the product of the half sum of the base lengths by the altitude.


In your case the half sum of the base lengths is 

 =  =  = .

Therefore, the area of your trapezoid is

 = .

It is what has to be proved.

Solved.


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