SOLUTION: I have to find all real and imaginary numbers. My guess is to factor, but I don't think it does. 3x(x)+ 2x + 1 = 0

Question 6274: I have to find all real and imaginary numbers. My guess is to factor, but I don't think it does.
3x(x)+ 2x + 1 = 0
Answer by xcentaur(357) (Show Source): You can put this solution on YOUR website!
3x^2 + 2x + 1 = 0

x=[-2 +- sqrt(4 - 4(3)(1))]/2(3)
x=[-2 +- sqrt(4 - 4(3)(1))]/2(3)
x=[-2 +- sqrt(4 - 12)]/6
x=[-2 +- sqrt(-8)]/6

Now the discriminant is less than zero (-8). Therefore there are no real solutions,both will be imaginary.

square root of -8 = +- 2.8284271247461900976033774484194

x=[-2 +- i(2.8284271247461900976033774484194)]/6

Hope this helps,
good luck

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