SOLUTION: x^2+8x+20=0 i dont know if these are complex numbers but the problem says solve the equation in the complex number system
Complex Numbers Imaginary Numbers Solvers and Lesson
-> SOLUTION: x^2+8x+20=0 i dont know if these are complex numbers but the problem says solve the equation in the complex number system
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i dont know if these are complex numbers but the problem says solve the equation in the complex number system
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ALL numbers are in the complex number system. Real numbers just happen to have an imaginary part coefficient of zero.
Use the discriminant to determine the nature of your roots:
For any quadratic polynomial equation of the form:
Find the Discriminant,
and evaluate the nature of the roots as follows:
No calculation quick look: If the signs on
are opposite, then
Two real and unequal roots. If
is a perfect square, the quadratic factors over
One real root with a multiplicity of two. That is to say that the trinomial is a perfect square and has two identical factors. Presuming rational coefficients, the root will be rational as well.
A conjugate pair of complex roots of the form
is the imaginary number defined by
For your problem, 64 - 80 = -16, so
Go right from here to the quadratic formula:
From here just simplify. Your two zeros will have the form
My calculator said it, I believe it, that settles it