SOLUTION: x^2+8x+20=0
i dont know if these are complex numbers but the problem says solve the equation in the complex number system
Algebra.Com
Question 619026: x^2+8x+20=0
i dont know if these are complex numbers but the problem says solve the equation in the complex number system
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
ALL numbers are in the complex number system. Real numbers just happen to have an imaginary part coefficient of zero.
Use the discriminant to determine the nature of your roots:
For any quadratic polynomial equation of the form:
Find the Discriminant, 
and evaluate the nature of the roots as follows:
No calculation quick look: If the signs on 
and 
are opposite, then 
guaranteed.
Two real and unequal roots. If 
is a perfect square, the quadratic factors over 
(the rationals).
One real root with a multiplicity of two. That is to say that the trinomial is a perfect square and has two identical factors. Presuming rational coefficients, the root will be rational as well.
A conjugate pair of complex roots of the form 
where 
is the imaginary number defined by 
For your problem, 64 - 80 = -16, so 
Go right from here to the quadratic formula: 
From here just simplify. Your two zeros will have the form 
John
My calculator said it, I believe it, that settles it
RELATED QUESTIONS
help! i dont understand this problem...i know what real and imaginary numbers are but... (answered by cartert,Mathtut,Fombitz)
how to we solve the following equation to find the complex number/roots?
x^2-8x+30=0
(answered by Alan3354)
Can someone help clear up something for me?
Are complex numbers the same as complex... (answered by Alan3354)
Solve in the complex number system.
8x^3 + 27 =... (answered by checkley71)
Solve the equation. Write any complex solutions in standard form for a complex number.... (answered by ikleyn)
Please help me solve the equation in the complex number system... (answered by stanbon)
Solve the equation in the complex number system.... (answered by solver91311)
solve the equation in the complex number system
8x^2+1=5x
(answered by jsmallt9)
what are the complex zeros of y=X^3 I think the real zero is "0" and the other 2... (answered by solver91311)
