SOLUTION: If z=1+4i, What is abs(z) (z)(abs z)=absolute z squared=a^2+b^2 Notice that z=a+ib

SOLUTION: If z=1+4i, What is abs(z) (z)(abs z)=absolute z squared=a^2+b^2 Notice that z=a+ib

Algebra.Com

Question 606412: If z=1+4i, What is abs(z)
(z)(abs z)=absolute z squared=a^2+b^2
Notice that z=a+ib
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!

RELATED QUESTIONS
What is the number of distinct solution of the equation {{{z^2+abs(z)}}} = {{{0}}}... (answered by ikleyn)

COMPLEX NUMBER If {{{z = a+bi}}} and {{{abs((z-i)/(z+2+i))=3}}}, show that {{{8a^2 +... (answered by Edwin McCravy)

Question: The absolute value of a complex number z = a + bi, denoted |z|, is given by the (answered by Edwin McCravy)

What is z-1/z-8 - z+1/z+8 + z-120/z^2-64... (answered by jim_thompson5910)

If z is a complex number satisfying z + \frac{1}{z} = \sqrt{2}, calculate z^{10} (answered by CPhill)

z= (3+4i)(12-5i)/(2+i) a. |z| ? b. Re (z) and Im (z)? I doubt ! thnx alot (answered by tommyt3rd)

z= (3+4i)(12-5i) /(2+i) a. |z| ? b. Re (z) and Im (z)? I doubt ! thnx... (answered by tommyt3rd)

with Z=2- j3, find a> jZ b> Z^* c> 1/Z d>... (answered by ikleyn)

Suppose Z is a standard normal random variable. 1. If P(-z < Z < z) = 0.5098, find z. (answered by Theo)