SOLUTION: I understand that i have to multiply so that the denomomintor is 1 but I dont know how to do that because the denominator is a binomal. Heres the problem, {{{b^-.5}}} over {{{

Question 59877This question is from textbook Algebra 2
: I understand that i have to multiply so that the denomomintor is 1 but I dont know how to do that because the denominator is a binomal.
Heres the problem,
over

If you have the time it would be appreciated if you could sohw me the steps This question is from textbook Algebra 2

Found 2 solutions by funmath, stanbon:
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!

The first thing I would do is move the things with negative exponents where they aren't (either numerator or denominator) and change the decimals to fractions.

:
If your problem was really in decimal form to begin with:

I am assuming that the denominator can't have a decimal in its exponent and it can't have a negative exponent.
Happy Calculating!!!
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
b^-.5 over 8b^.333b^-.25
=(1/8)b^(-0.5-0.333+0.25)
=(1/8)b^-0.583
=1/[8b^0.583]
Cheers,
Stan H.
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