SOLUTION: find the complex zeros of the polynomial function write f in the factored form. x^3+216 so far I have done: x^3 + 6^3 (a+b)(a^2-ab+b^2) = (x+6)(x^2-6x+36) quadratic fo

Question 596404: find the complex zeros of the polynomial function write f in the factored form. x^3+216
so far I have done:
x^3 + 6^3
(a+b)(a^2-ab+b^2) = (x+6)(x^2-6x+36)
quadratic formula: -b plus or minus square root (b^2 - 4 * a * c)/2
6 +- square root (36 - 144)/2
I am confused on the simplified answer not the math in general so would I leave
6 +- square root 108 in that form divided by 2 or what?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
find the complex zeros of the polynomial function write f in the factored form. x^3+216
so far I have done:
x^3 + 6^3
(a+b)(a^2-ab+b^2) = (x+6)(x^2-6x+36)
quadratic formula: -b plus or minus square root (b^2 - 4 * a * c)/2
6 +- square root (36 - 144)/2
I am confused on the simplified answer not the math in general so would I leave
6 +- square root 108 in that form divided by 2 or what?
-----------
-------
If you meant x^3 + 216 = 0, then

x = -6
-----

Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

The discriminant -108 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.

In the field of imaginary numbers, the square root of -108 is + or - .

The solution is , or
Here's your graph:

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