SOLUTION: (6-4i) - (3-2i) (3+i)(2-7i) 4+3i/3-2i

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Question 58114: (6-4i) - (3-2i)
(3+i)(2-7i)
4+3i/3-2i
Answer by funmath(2873) About Me  (Show Source):
You can put this solution on YOUR website!
1.
%286-4i%29-%283-2i%29
6-4i-3%2B2i
6-3-4i%2B2i
highlight%283-2i%29
:
2.
%283%2Bi%29%282-7i%29
3%282-7i%29%2Bi%282-7i%29
6-21i%2B2i-7i%5E2 Remember i%5E2=-1
6-19i-7%28-1%29
6-19i%2B7
highlight%2813-19i%29
:
3.
%284%2B3i%29%2F%283-2i%29 Multiply the numerator and denominator by the conjugate of the denominator (3+2i)
%284%2B3i%29%283%2B2i%29%2F%28%283-2i%29%283%2B2i%29%29
%284%283%2B2i%29%2B3i%283%2B2i%29%29%2F%283%283%2B2i%29-2i%283%2B2i%29%29
%2812%2B8i%2B9i%2B6i%5E2%29%2F%289%2B6i-6i-4i%5E2%29
%2812%2B17i%2B6%28-1%29%29%2F%289-4%28-1%29%29
%2812%2B17i-6%29%2F%289%2B4%29
6%2B17i%29%2F13 Remember standard form is a+bi
highlight%286%2F13%2B%2817%2F13%29i%29
:
Happy Calculators!!!