SOLUTION: I have a few I am totally stuck on.
#1)2/x+3 - 2x+3/x-1 = 6x-5/x^2+2x-3
Okay so I know that the LCD here is going to be (x+3) and (x+1) but I can not figure out how to d
Algebra.Com
Question 563537: I have a few I am totally stuck on.
#1)2/x+3 - 2x+3/x-1 = 6x-5/x^2+2x-3
Okay so I know that the LCD here is going to be (x+3) and (x+1) but I can not figure out how to distribute it.
#2.)x^2-10/x^2-x-20 = 1 + 7/x-5
Here I have I think the LCD is (x-5) (x+4) but again am not being able to figure out how to distribute it properly.
#3)5y^(negative)2 +1=6y^(negative)1
No clue the negative exponents are really throwing me here....Thanks so much for your help
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
LCD = (x+3) (x-1)
Multiply the equation by LCD
=
(x+6)(2x+1)=0
x=-6 OR -0.5
m.ananth@hotmail.ca
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