# SOLUTION: If I invest \$25,000 in two different stocks. One earns 6.5% and the other earns 7.00%. If the total interest earnings for one year is 1683.75, how much is invested in each stock

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: If I invest \$25,000 in two different stocks. One earns 6.5% and the other earns 7.00%. If the total interest earnings for one year is 1683.75, how much is invested in each stock      Log On

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 Question 54880: If I invest \$25,000 in two different stocks. One earns 6.5% and the other earns 7.00%. If the total interest earnings for one year is 1683.75, how much is invested in each stock? Stock X = ? = 6.5% interest Stock Y = ? = 7.0% interest Total = \$25,000 = 1,683.75 Total interest Please show me how to solve this problem.Found 2 solutions by stanbon, tutorcecilia:Answer by stanbon(60772)   (Show Source): You can put this solution on YOUR website!If I invest \$25,000 in two different stocks. One earns 6.5% and the other earns 7.00%. If the total interest earnings for one year is 1683.75, how much is invested in each stock? ------------ Let amount invested at 6.5% be "x". Interest on this money is 0.065x dollars. -------- Amount invested at 7% is "25000-x" INterest on this money is 0.07(25000-x)=1750-0.07x dollars ------------- EQUATION: interest + interest = 1683.75 0.065x + 1750-0.07x = 1683.75 -0.005x=-66.25 x=\$13,250 (amount invested at 6.5%) 25000-x=\$38,250 (amount invested at 7%) Cheers, Stan H. Answer by tutorcecilia(2152)   (Show Source): You can put this solution on YOUR website!Ax+By=C [Use the standand formula of a line] A=the rate, percent or cost of item A x=the amount or number of item A B=the rate, percent or cost of item B y=the rate, percent or cost of item B C=(the total amount)(average rate) x+y=C so y=(Total amount of C-x] or y=C-x [Substitution for the y variable] . (0.065)(x)+(0.07)(25,000-x)= 1683.75 [Plug-in the values] 0.065x+1750-0.07-x= 1683.75 [Simplify] 0.065x-0.07-x= 1683.75-1750 [Solve for x] -.005x=-66.26 x=\$13,250 . (6.5%)(\$13,250)=(0.065)(13,250)=\$861.25 invested at 6.5% (7.0%)(\$25,000-x)=0.07(25,000-13,250)=1750-927.50=\$822.50 invested at 7.0% So, \$861.25+\$822.50=\$1683.75