SOLUTION: If arg((z-w)/(z-w^2)) =0,then prove that re(z)=-1/2,where (w and w^2 are non real cube roots of unity)
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Question 540721: If arg((z-w)/(z-w^2)) =0,then prove that re(z)=-1/2,where (w and w^2 are non real cube roots of unity)
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
If the argument of some complex number is 0, then the number must be a positive real number. Also, the numerator (z - omega) can be set to zero. We have
 = -\frac{1}{2})
Since we want  = 0)
we set  = \frac{1}{2})
.
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